Simplifying F(x) = 25x Multiply F * x xF = 25x Solving xF = 25x Solving for variable 'x' Move all terms containing x to the left, all other terms to the right Add '25x' to each side of the equation 25x xF = 25x 25x Combine like terms 25x 25x = 00 25x xF = 00 Factor out the Greatest Common Factor (GCF), 'x' x(25 F) = 001 solution(s) found fx4x^25 See steps Step by Step Solution Reformatting the input Changes made to your input should not affect the solution (1) "x2" was replaced by "x^2"1) is a critical point The second derivative test f xx = 2;f yy = 2;f xy = 0 shows this a local minimum with

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F(x)=-x 5/2-1/2 ex-2(ex-2-4)-X^2 WolframAlpha Volume of a cylinder?Find the Derivative f(x)=x^(4/5)(x4)^2 Rewrite as Expand using the FOIL Method Tap for more steps Apply the distributive property Apply the distributive property Apply the distributive property Simplify and combine like terms Tap for more steps Simplify each term Tap for more steps Multiply by




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Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!The steps are simple 1 Use the information in the question to work out the value of mathx/math 2 Calculate mathx 3/math Step 1To find equation solutions, solve x1=0 and x1=0 Take the square root of both sides of the equation Subtract 1 from both sides This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 0 for b, and 1 for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} Square 0 Multiply 4 times 1
Let f(x)=x21/x2 and g(x)=x1/x,x∈ R {1,0,1} If h(x)=f(x)/g(x), then the local minimum value of h(x) is (1) 3 (2) – 3 (3) − 2√2 (4) 2√2Δ = b 24ac Δ = 5 24·(1)·(5) Δ = 5 The delta value is higher than zero, soWeekly Subscription $199 USD per week until cancelled Monthly Subscription $699 USD per month until cancelled Annual Subscription $2999 USD per year until cancelled
I assume you mean How can I find F(2) if F (x^2–5x4) = x3?(a) f′′(x) ≤ 0 for x ≥ 0 (b) Since t2/2 is convex we have t2/2 ≥ x2/2x(t−x) = xt−x2/2 This is the general inequality g(t) ≥ g(x)g′(x)(t−x), which holds for any differentiable convex function, applied to g(t) = t2/2 Another (easier?) way to establish t2/2 ≤ −x2/2xt is to note that t2/2x2/2−xt = (1/2)(x−t)2 ≥ 0 Now just move x2/2−xt to the other side Explanation f (x) = {x2 if x ≥ 1 2x if x < 1 f is continuous at 1 if and only if lim x→1 f (x) = f (1) (existence of both is implied) We see from the definition of f above that f (1) = (1)2 = 1 In finding the limit, we'll need to consider the left and right limits separately because the rule changes at x = 1 The limit from the right is



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2x25x=3 Two solutions were found x = 3 x = 1/2 = 0500 Rearrange Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation Hint If (this was the original post) $$2f(x) f(1x) = x^2$$ then $$2f(1x) f(x) = (1x)^2$$ So, multiplying the first by $2$ and adding to the second, we have $$3f(x)=2x^2(1x)^2$$All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x=\frac {\left (3\right)±\sqrt {\left (3\right)^ {2}4\left (1\right)\times 5}} {2\left (1



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Simple and best practice solution for F(x)=(x5)(2x1) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkAlgebra Find the Properties f (x)= (x5)^2 f (x) = (x − 5)2 f ( x) = ( x 5) 2 Use the vertex form, y = a(x−h)2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 h = 5 h = 5 k = 0 k = 0 Since the value of a a is positive, the parabola opens up Opens UpSimple and best practice solution for f(x)=2(x2)(x4)4 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework




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F(x)4x25 This deals with factoring multivariable polynomials Overview;Use the distributive property to multiply 3 x 4 − 1 8 x 3 2 4 x 2 by x 1 and combine like terms 3x^{5}15x^{4}6x^{3}24x^{2} 3 x 5 − 1 5 x 4 6 x 3 2 4 x 2Δ = b 24ac Δ = 4 24·(1)·5 Δ = 36 The delta value is higher than zero, so the equation



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At 𝑥 = 2 ?Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyYeah, that's for it That means that F of X is equal to X to the 5th minus X cubed for acts class C Ever We're told that F of 1 equals two So f of negative one Is going to give us right here, this will be a 1 This will be a negative one Supposed to be plus one This will be a negative for some 4



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